Thursday, February 26, 2009

vedic maths sutra2

ĀNURŨPYE ŚŨNYAMANYAT

The Sutra Anurupye Sunyamanyat says : 'If one is in ratio, the other one is zero'.

We use this Sutra in solving a special type of simultaneous simple equations in which the coefficients of 'one' variable are in the same ratio to each other as the independent terms are to each other. In such a context the Sutra says the 'other' variable is zero from which we get two simple equations in the first variable (already considered) and of course give the same value for the variable.

Example 1:
3x + 7y = 2
4x + 21y = 6

Observe that the y-coefficients are in the ratio 7 : 21 i.e., 1 : 3, which is same as the ratio of independent terms i.e., 2 : 6 i.e., 1 : 3. Hence the other variable x = 0 and 7y = 2 or 21y = 6 gives y = 2 / 7

Example 2:
323x + 147y = 1615
969x + 321y = 4845

The very appearance of the problem is frightening. But just an observation and anurupye sunyamanyat give the solution x = 5, because coefficient of x ratio is
323 : 969 = 1 : 3 and constant terms ratio is 1615 : 4845 = 1 : 3.
y = 0 and 323 x = 1615 or 969 x = 4845 gives x = 5.

Wednesday, February 25, 2009

sutra 1 of vedic maths

EKĀDHIKENA PŪRVEŅA

The Sutra (formula) Ekādhikena Pūrvena means: “By one more than the previous one”.

i) Squares of numbers ending in 5 :

Now we relate the sutra to the ‘squaring of numbers ending in 5’. Consider the example 252.

Here the number is 25. We have to find out the square of the number. For the number 25, the last digit is 5 and the 'previous' digit is 2. Hence, 'one more than the previous one', that is, 2+1=3. The Sutra, in this context, gives the procedure 'to multiply the previous digit 2 by one more than itself, that is, by 3'. It becomes the L.H.S (left hand side) of the result, that is, 2 X 3 = 6. The R.H.S (right hand side) of the result is 52, that is, 25.

Thus 252 = 2 X 3 / 25 = 625.

In the same way,

352= 3 X (3+1) /25 = 3 X 4/ 25 = 1225;

652= 6 X 7 / 25 = 4225;

1052= 10 X 11/25 = 11025;

1352= 13 X 14/25 = 18225;

vedic maths(fastest maths ever!) tutorial1

Tutorial 1

Use the formula ALL FROM 9 AND THE LAST FROM 10 to perform instant subtractions.

  • For example 1000 - 357 = 643

    We simply take each figure in 357 from 9 and the last figure from 10.

    So the answer is 1000 - 357 = 643

    And thats all there is to it!

    This always works for subtractions from numbers consisting of a 1 followed by noughts: 100; 1000; 10,000 etc.

  • Similarly 10,000 - 1049 = 8951
  • For 1000 - 83, in which we have more zeros than figures in the numbers being subtracted, we simply suppose 83 is 083.

    So 1000 - 83 becomes 1000 - 083 = 917

vedic maths(fastest maths ever!) t

Tuesday, February 24, 2009

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